RE: Implementation 3 Stuck terms

From: Rui Shi (shearer@cs.bu.edu)
Date: Sun Oct 29 2006 - 11:00:15 EST


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From: "Rui Shi" <shearer@cs.bu.edu>
To: <samepst@cs.bu.edu>, <cs520@cs.bu.edu>
Subject: RE: Implementation 3 Stuck terms
Date: Sun, 29 Oct 2006 11:00:15 -0500
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It is correct according to the rules. Then in substitution, you don't need
to consider substitution for raise for simplicity.

Rui

-----Original Message-----
From: samepst@cs.bu.edu [mailto:samepst@cs.bu.edu]
Sent: Sunday, October 29, 2006 12:45 AM
To: cs520@cs.bu.edu
Subject: Re: Implementation 3 Stuck terms

This is unexpected. My typechecker types (lam (Exit:int)=> raise Exit) to

TpFun (TpBase "int", TpBase "any")

based on the typing rules ty-lam, ty-exn, and ty-raise. What is the reason
for its failure to typecheck?

Thank You,
-Sam Epstein

> Before you consider substitution -- I assume you are referring to
> substitution of the argument "5" for the formal parameter "Exit" in
> the body of the lambda-abstraction -- you should verify that the
> lambda-abstraction in question "(lam (Exit:int)=> raise Exit)"
> type-checks. It does not.
>
> Assaf
>
> samepst@cs.bu.edu wrote:
>
>>Is it correct to assume that substituion does not recurse into raise
>>terms?
>>For example, the following terms evaluates to true:
>>
>>try (lam (Exit:int)=> raise Exit) 5 with Exit => true | 5 => false
>>
>>Thank you,
>>Sam Epstein
>>
>>
>>
>



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